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Solution :

`y^2=4*a=36`<br>
`y=pm6`<br>
`y^2=4x`<br>
diff with respect to x<br>
`2y*y'=4`<br>
`y'=2/y`<br>
`(m)_(9,6)=1/3`<br>
slope is at tangent(9,6)<br>
`m'*m=-1`<br>
`m'=-3`<br>
slope of normal<br>
`y=m'x+c`<br>
`y=-3x+c`<br>
`6=-3*9+c`<br>
`c=6+27=33`<br>
`y=-3x+33`<br>
`3x+y=33`<br>
option b is correct.
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